What is (x+1)^2+(y-3)^2=(sqrt(50))^2 ?

The solution to (x+1)^2+(y-3)^2=(sqrt(50))^2 is Circle with (a,b)=(-1,3),r=sqrt((\sqrt{50))^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+1)^2+(y-3)^2=(sqrt(50))^2

(x + 1)^{2} + (y - 3)^{2} = (50)^{2}

(a, b) = (- 1, 3), r = (50)^{2}

Solution steps

(x + 1)^{2} + (y - 3)^{2} = (50)^{2}

Rewrite

(x + 1)^{2} + (y - 3)^{2} = 50^{2}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = ((50)^{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = (50)^{2}

\frac{( x - 5 ) ^{2}}{3 ^{2}} + \frac{( y + 5 ) ^{2}}{9} = 1

x^{2} - 2 x + y^{2} + 4 y = 31

x^{2} + y^{2} - 4 x + 2 y + 2 = 0

x^{2} + y^{2} + 6 y + 3 = 0

x^{2} + y^{2} + x - \frac{1}{2} y = 0

What is (x+1)^2+(y-3)^2=(sqrt(50))^2 ?
The solution to (x+1)^2+(y-3)^2=(sqrt(50))^2 is Circle with (a,b)=(-1,3),r=sqrt((\sqrt{50))^2}