What is (x+8)^2+(y+13)^2=58 ?

The solution to (x+8)^2+(y+13)^2=58 is Circle with (a,b)=(-8,-13),r=sqrt(58)

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(x+8)^2+(y+13)^2=58

(x + 8)^{2} + (y + 13)^{2} = 58

(a, b) = (- 8, - 13), r = 58

Solution steps

(x + 8)^{2} + (y + 13)^{2} = 58

Rewrite

(x + 8)^{2} + (y + 13)^{2} = 58

in the form of the standard circle equation

(x - (- 8))^{2} + (y - (- 13))^{2} = (58)^{2}

Therefore the circle properties are:

(a, b) = (- 8, - 13), r = 58

2 x + 2 y = x^{2} + y^{2}

13 x^{2} + 13 y^{2} - 19 x + 5 y - 132 = 0

x^{2} + y^{2} - 10 x + 2 y + 1 = 0

x^{2} + y^{2} - 4 x + 2 y - 8 = 0

0.5 9^{2} = (x - (- 0.02))^{2} + (y - 0.78)^{2}

What is (x+8)^2+(y+13)^2=58 ?
The solution to (x+8)^2+(y+13)^2=58 is Circle with (a,b)=(-8,-13),r=sqrt(58)