What is (x+7)^2+(y+4)^2=49 ?

The solution to (x+7)^2+(y+4)^2=49 is Circle with (a,b)=(-7,-4),r=7

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(x+7)^2+(y+4)^2=49

(x + 7)^{2} + (y + 4)^{2} = 49

(a, b) = (- 7, - 4), r = 7

Solution steps

(x + 7)^{2} + (y + 4)^{2} = 49

Rewrite

(x + 7)^{2} + (y + 4)^{2} = 49

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 4))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 4), r = 7

x^{2} - 8 x + y^{2} - 9 = 0

4 x^{2} + 10 x + 4 y^{2} - y - 4 = 0

3 x^{2} + 3 y^{2} + 8 x + 6 y + 7 = 0

36 x^{2} + 36 y^{2} - 48 x - 36 y + 16 = 0

3 x^{2} + 3 y^{2} - 15 - 0 = 0

What is (x+7)^2+(y+4)^2=49 ?
The solution to (x+7)^2+(y+4)^2=49 is Circle with (a,b)=(-7,-4),r=7