What is 9x^2+9y^2+12y+36y-104=0 ?

The solution to 9x^2+9y^2+12y+36y-104=0 is Circle with (a,b)=(0,-8/3),r=(2sqrt(14))/(sqrt(3))

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9x^2+9y^2+12y+36y-104=0

9 x^{2} + 9 y^{2} + 12 y + 36 y - 104 = 0

(a, b) = (0, - \frac{8}{3}), r = \frac{2 14}{3}

Solution steps

9 x^{2} + 9 y^{2} + 12 y + 36 y - 104 = 0

Rewrite

9 x^{2} + 9 y^{2} + 12 y + 36 y - 104 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- \frac{8}{3}))^{2} = (\frac{2 14}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, - \frac{8}{3}), r = \frac{2 14}{3}

4 x^{2} + 4 y^{2} - 32 y + 39 = 0

x^{2} + 12 x + y^{2} - 12 y = - 56

(x - 1)^{2} + (y + 6)^{2} \leq 4

(x - 10)^{2} + (y + 1)^{2} - 64 = 0

- 3 y^{2} = 3 x^{2} - 2 x - 1

What is 9x^2+9y^2+12y+36y-104=0 ?
The solution to 9x^2+9y^2+12y+36y-104=0 is Circle with (a,b)=(0,-8/3),r=(2sqrt(14))/(sqrt(3))