What is 3x^2+3y^2-24x-24y-51=0 ?

The solution to 3x^2+3y^2-24x-24y-51=0 is Circle with (a,b)=(4,4),r=7

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3x^2+3y^2-24x-24y-51=0

3 x^{2} + 3 y^{2} - 24 x - 24 y - 51 = 0

(a, b) = (4, 4), r = 7

Solution steps

3 x^{2} + 3 y^{2} - 24 x - 24 y - 51 = 0

Rewrite

3 x^{2} + 3 y^{2} - 24 x - 24 y - 51 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 4)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (4, 4), r = 7

(x - (- 2))^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} \leq 64

(x - \frac{1}{2})^{2} + y^{2} = \frac{1}{4}

x^{2} + y^{2} + 2 x - 2 y + 1 = 0

y^{2} + x^{2} = 64

What is 3x^2+3y^2-24x-24y-51=0 ?
The solution to 3x^2+3y^2-24x-24y-51=0 is Circle with (a,b)=(4,4),r=7