What is ((x-2)^2)/9-(y+1)^2=1 ?

The solution to ((x-2)^2)/9-(y+1)^2=1 is Hyperbola with (h,k)=(2,-1),a=3,b=1

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((x-2)^2)/9-(y+1)^2=1

\frac{( x - 2 ) ^{2}}{9} - (y + 1)^{2} = 1

(h, k) = (2, - 1), a = 3, b = 1

Solution steps

\frac{( x - 2 ) ^{2}}{9} - (y + 1)^{2} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{9} - (y + 1)^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 1), a = 3, b = 1

37.2 y = x^{2}

x^{2} - y^{2} = 25

x^{2} + 4 y^{2} = 1

\frac{x ^{2}}{25} + y^{2} = 1

\frac{( y - 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{16} = 1

What is ((x-2)^2)/9-(y+1)^2=1 ?
The solution to ((x-2)^2)/9-(y+1)^2=1 is Hyperbola with (h,k)=(2,-1),a=3,b=1