What is (x-8)^2+(y-3)^2=sqrt(3) ?

The solution to (x-8)^2+(y-3)^2=sqrt(3) is Circle with (a,b)=(8,3),r=sqrt(\sqrt{3)}

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(x-8)^2+(y-3)^2=sqrt(3)

(x - 8)^{2} + (y - 3)^{2} = 3

(a, b) = (8, 3), r = 3

Solution steps

(x - 8)^{2} + (y - 3)^{2} = 3

Rewrite

(x - 8)^{2} + (y - 3)^{2} = 3

in the form of the standard circle equation

(x - 8)^{2} + (y - 3)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (8, 3), r = 3

(x^{2} + 5 x + \frac{25}{4}) + y^{2} = \frac{25}{4} + \frac{25}{4}

x^{2} + y^{2} + 8 x + 6 y + 9 = 0

x^{2} + y^{2} + 4 x - 2 y - 5 = 0

a^{2} + b^{2} = 15.5 6^{2}

x^{2} - 4 x + y^{2} + 3 y = 0

What is (x-8)^2+(y-3)^2=sqrt(3) ?
The solution to (x-8)^2+(y-3)^2=sqrt(3) is Circle with (a,b)=(8,3),r=sqrt(\sqrt{3)}