What is (x-8)^2+(y-3)^2=sqrt(9) ?

The solution to (x-8)^2+(y-3)^2=sqrt(9) is Circle with (a,b)=(8,3),r=sqrt(\sqrt{9)}

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(x-8)^2+(y-3)^2=sqrt(9)

(x - 8)^{2} + (y - 3)^{2} = 9

(a, b) = (8, 3), r = 9

Solution steps

(x - 8)^{2} + (y - 3)^{2} = 9

Rewrite

(x - 8)^{2} + (y - 3)^{2} = 9

in the form of the standard circle equation

(x - 8)^{2} + (y - 3)^{2} = (9)^{2}

Therefore the circle properties are:

(a, b) = (8, 3), r = 9

(x - 4.5)^{2} + (y - 1.5)^{2} = 5.52

x^{2} + y^{2} + 2 x + 1 < 1

4 x^{2} + 4 y^{2} - 9 = 0

4 x^{(2)} + 4 y^{(2)} - 8 y - 5 = 0

4 y^{2} + 24 y + 4 x^{2} - 12 + 9 = 0

What is (x-8)^2+(y-3)^2=sqrt(9) ?
The solution to (x-8)^2+(y-3)^2=sqrt(9) is Circle with (a,b)=(8,3),r=sqrt(\sqrt{9)}