What is (x+8)^2+(y-6)^2=100 ?

The solution to (x+8)^2+(y-6)^2=100 is Circle with (a,b)=(-8,6),r=10

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(x+8)^2+(y-6)^2=100

(x + 8)^{2} + (y - 6)^{2} = 100

(a, b) = (- 8, 6), r = 10

Solution steps

(x + 8)^{2} + (y - 6)^{2} = 100

Rewrite

(x + 8)^{2} + (y - 6)^{2} = 100

in the form of the standard circle equation

(x - (- 8))^{2} + (y - 6)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 8, 6), r = 10

2 x^{2} + 2 y^{2} + 6 x - 8 y - 3 = 0

3 0^{2} = a^{2} + b^{2}

x^{2} + y^{2} + 6 x - 8 y + 5 = 0

(x + π)^{2} + (y - 2 π)^{2} = 8

18 y - 15 = - x^{2} - y^{2}

What is (x+8)^2+(y-6)^2=100 ?
The solution to (x+8)^2+(y-6)^2=100 is Circle with (a,b)=(-8,6),r=10