What is x^2+y^2-3x=39-6y ?

The solution to x^2+y^2-3x=39-6y is Circle with (a,b)=(3/2 ,-3),r=(sqrt(201))/2

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x^2+y^2-3x=39-6y

x^{2} + y^{2} - 3 x = 39 - 6 y

(a, b) = (\frac{3}{2}, - 3), r = \frac{201}{2}

Solution steps

x^{2} + y^{2} - 3 x = 39 - 6 y

Rewrite

x^{2} + y^{2} - 3 x = 39 - 6 y

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- 3))^{2} = (\frac{201}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - 3), r = \frac{201}{2}

x^{(2)} + (y - 4)^{(2)} = 16

x^{2} + y^{2} + 5 = 6 y

x^{2} + y^{2} - 60 x + 16 y + 739 = 0

- y^{2} - x^{2} = - 9

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = 1

What is x^2+y^2-3x=39-6y ?
The solution to x^2+y^2-3x=39-6y is Circle with (a,b)=(3/2 ,-3),r=(sqrt(201))/2