What is (x-(-4))^2+(y-(2))^2=3^2 ?

The solution to (x-(-4))^2+(y-(2))^2=3^2 is Circle with (a,b)=(-4,2),r=3

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(x-(-4))^2+(y-(2))^2=3^2

(x - (- 4))^{2} + (y - (2))^{2} = 3^{2}

(a, b) = (- 4, 2), r = 3

Solution steps

(x - (- 4))^{2} + (y - 2)^{2} = 3^{2}

Rewrite

(x - (- 4))^{2} + (y - 2)^{2} = 3^{2}

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, 2), r = 3

(x - 12)^{2} + y^{2} = 144

(2 x^{2} + 6 x + 9) + (2 y^{2} + 2 y + 1) = 45 + 9 + 1

4 x^{2} + 4 y^{2} - 16 x - 28 y + 41 = 0

y^{2} = - x^{2} + 196

(x + 7)^{2} + (y - 1)^{2} = 16

What is (x-(-4))^2+(y-(2))^2=3^2 ?
The solution to (x-(-4))^2+(y-(2))^2=3^2 is Circle with (a,b)=(-4,2),r=3