What is x^2+y^2-2x+4y=11 ?

The solution to x^2+y^2-2x+4y=11 is Circle with (a,b)=(1,-2),r=4

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x^2+y^2-2x+4y=11

x^{2} + y^{2} - 2 x + 4 y = 11

(a, b) = (1, - 2), r = 4

Solution steps

x^{2} + y^{2} - 2 x + 4 y = 11

Rewrite

x^{2} + y^{2} - 2 x + 4 y = 11

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 4

x^{2} + y^{2} - x + 3 y - \frac{15}{4} = 0

x^{2} + y^{2} + 6 x - 10 y - 2 = 0

(x + \frac{1}{2})^{2} + (y + 3)^{2} = \frac{1}{2 ^{2}}

x^{2} + 4 x + y^{2} + 4 y - 8 = 0

(x - 8)^{2} + (y + 3)^{2} = 1

What is x^2+y^2-2x+4y=11 ?
The solution to x^2+y^2-2x+4y=11 is Circle with (a,b)=(1,-2),r=4