What is (x+5)^2+(y+6)^2=12 ?

The solution to (x+5)^2+(y+6)^2=12 is Circle with (a,b)=(-5,-6),r=sqrt(12)

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(x+5)^2+(y+6)^2=12

(x + 5)^{2} + (y + 6)^{2} = 12

(a, b) = (- 5, - 6), r = 12

Solution steps

(x + 5)^{2} + (y + 6)^{2} = 12

Rewrite

(x + 5)^{2} + (y + 6)^{2} = 12

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 6))^{2} = (12)^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 6), r = 12

x^{2} + y^{2} - x - y - 16 = 0

(x^{2} + 2 x) + (y^{2} + 4 y) = - 1

x^{2} + y^{2} - 4 x - 6 y - 36 = 0

(x + 9)^{2} + (y - 8)^{2} = 81

x, x^{2} + Y (x)^{2} = 100 + 5 Y

What is (x+5)^2+(y+6)^2=12 ?
The solution to (x+5)^2+(y+6)^2=12 is Circle with (a,b)=(-5,-6),r=sqrt(12)