What is -x^2-y^2+5=x+y+1 ?

The solution to -x^2-y^2+5=x+y+1 is Circle with (a,b)=(-1/2 ,-1/2),r= 3/(sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-x^2-y^2+5=x+y+1

- x^{2} - y^{2} + 5 = x + y + 1

(a, b) = (- \frac{1}{2}, - \frac{1}{2}), r = \frac{3}{2}

Solution steps

- x^{2} - y^{2} + 5 = x + y + 1

Rewrite

- x^{2} - y^{2} + 5 = x + y + 1

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - (- \frac{1}{2}))^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, - \frac{1}{2}), r = \frac{3}{2}

x^{2} + y^{2} + 8 x - 6 y = 6

x^{2} - 8 x + y^{2} - 2 y - 19 = 0

(x + 5)^{2} + (y + 0.6666600000000 \dots)^{2} = 0.4444400000000 \dots

x^{2} + y^{2} = 19.4 x + 3 y - 4

- y^{2} + 4 = x^{2}

What is -x^2-y^2+5=x+y+1 ?
The solution to -x^2-y^2+5=x+y+1 is Circle with (a,b)=(-1/2 ,-1/2),r= 3/(sqrt(2))