What is (x-8)^2+(y+2)^2=324 ?

The solution to (x-8)^2+(y+2)^2=324 is Circle with (a,b)=(8,-2),r=18

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(x-8)^2+(y+2)^2=324

(x - 8)^{2} + (y + 2)^{2} = 324

(a, b) = (8, - 2), r = 18

Solution steps

(x - 8)^{2} + (y + 2)^{2} = 324

Rewrite

(x - 8)^{2} + (y + 2)^{2} = 324

in the form of the standard circle equation

(x - 8)^{2} + (y - (- 2))^{2} = 1 8^{2}

Therefore the circle properties are:

(a, b) = (8, - 2), r = 18

(- x + 3)^{2} + (y + 2)^{2} = 2^{2}

1^{2} = \frac{x ^{2}}{4} + \frac{y ^{2}}{4}

(x + 3)^{2} + (y - 4)^{2} = 1

x^{2} + y^{2} + 6 x + 6 y = 0

x^{2} - 4 x + y^{2} + 14 y = 11

What is (x-8)^2+(y+2)^2=324 ?
The solution to (x-8)^2+(y+2)^2=324 is Circle with (a,b)=(8,-2),r=18