What is (x-2)^2+(y+2)^2=25 ?

The solution to (x-2)^2+(y+2)^2=25 is Circle with (a,b)=(2,-2),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2+(y+2)^2=25

(x - 2)^{2} + (y + 2)^{2} = 25

(a, b) = (2, - 2), r = 5

Solution steps

(x - 2)^{2} + (y + 2)^{2} = 25

Rewrite

(x - 2)^{2} + (y + 2)^{2} = 25

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (2, - 2), r = 5

(x + 1)^{2} + (y - \frac{2}{3})^{2} = \frac{281}{3}^{2}

x^{2} + y^{2} + 8 y - 128 = 0

2 x^{2} + 2 y^{2} + 8 x - 12 y - 6 = 0

(x - 6)^{2} + (y - 9)^{2} = 49

x^{2} + y^{2} + 12 x - 2 y - 1 = 0

What is (x-2)^2+(y+2)^2=25 ?
The solution to (x-2)^2+(y+2)^2=25 is Circle with (a,b)=(2,-2),r=5