What is x^2-8y+6x+y^2-30=0 ?

The solution to x^2-8y+6x+y^2-30=0 is Circle with (a,b)=(-3,4),r=sqrt(55)

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x^2-8y+6x+y^2-30=0

x^{2} - 8 y + 6 x + y^{2} - 30 = 0

(a, b) = (- 3, 4), r = 55

Solution steps

x^{2} - 8 y + 6 x + y^{2} - 30 = 0

Rewrite

x^{2} - 8 y + 6 x + y^{2} - 30 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = (55)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 55

x^{2} + y^{2} - 26 x + 2 y + 120 = 0

x^{2} + y^{2} - 8 x - 8 (2 x + 1) + 27 = 0

(x - 4)^{2} + (y - 7)^{2} = (13)^{2}

(x - 2)^{2} + (y + 7)^{2} = 16

x^{2} + y^{2} + 2 x - 6 y - 35 = 0

What is x^2-8y+6x+y^2-30=0 ?
The solution to x^2-8y+6x+y^2-30=0 is Circle with (a,b)=(-3,4),r=sqrt(55)