What is x^2-1=0-y^2+1 ?

The solution to x^2-1=0-y^2+1 is Circle with (a,b)=(0,0),r=sqrt(2)

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x^2-1=0-y^2+1

x^{2} - 1 = 0 - y^{2} + 1

(a, b) = (0, 0), r = 2

Solution steps

x^{2} - 1 = 0 - y^{2} + 1

Rewrite

x^{2} - 1 = 0 - y^{2} + 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

- x^{2} - y^{2} = - 1

- x^{2} - y^{2} + 2 x - 3 y + \frac{3}{4} = 0

(x - 5)^{2} + (y + 2)^{2} = 15

(x + 1)^{2} + (y - 4)^{2} = 30

2 x^{2} + 2 y^{2} - 8 x - 16 y + 22 = 0

What is x^2-1=0-y^2+1 ?
The solution to x^2-1=0-y^2+1 is Circle with (a,b)=(0,0),r=sqrt(2)