What is (x+2)^2+(y+1)^2= 13/2 ?

The solution to (x+2)^2+(y+1)^2= 13/2 is Circle with (a,b)=(-2,-1),r=sqrt(13/2)

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(x+2)^2+(y+1)^2= 13/2

(x + 2)^{2} + (y + 1)^{2} = \frac{13}{2}

(a, b) = (- 2, - 1), r = \frac{13}{2}

Solution steps

(x + 2)^{2} + (y + 1)^{2} = \frac{13}{2}

Rewrite

(x + 2)^{2} + (y + 1)^{2} = \frac{13}{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 1))^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 1), r = \frac{13}{2}

3 - y = x^{2} + y^{2}

3 x^{2} + 3 y^{2} + 12 x + 12 y = 4

2 x^{2} + 2 y^{2} - 12 x + 4 y - 12 = 0

(x - 3)^{2} + (y - 5)^{2} = 144

x^{2} + y^{2} - 16 x + 40 y + 67 = 0

What is (x+2)^2+(y+1)^2= 13/2 ?
The solution to (x+2)^2+(y+1)^2= 13/2 is Circle with (a,b)=(-2,-1),r=sqrt(13/2)