What is (x-0)^2+(y-0)^2=7^2 ?

The solution to (x-0)^2+(y-0)^2=7^2 is Circle with (a,b)=(0,0),r=7

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(x-0)^2+(y-0)^2=7^2

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

(a, b) = (0, 0), r = 7

Solution steps

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

Rewrite

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 7

(x + 1)^{2} + (y - 3)^{2} = 1

(x + 1)^{2} + (y - 3)^{2} = 2

\frac{( 2 x - 2 ) ^{2}}{2} + \frac{( 2 y + 6 ) ^{2}}{2} = \frac{46}{2}

x^{2} + y^{2} - 8 x + 10 y + 32 = 0

x^{2} + (y - \frac{16}{3})^{2} = 49

What is (x-0)^2+(y-0)^2=7^2 ?
The solution to (x-0)^2+(y-0)^2=7^2 is Circle with (a,b)=(0,0),r=7