What is x^2+y^2=(-x-y+2)/2 ?

The solution to x^2+y^2=(-x-y+2)/2 is Circle with (a,b)=(-1/4 ,-1/4),r= 3/(2sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2=(-x-y+2)/2

x^{2} + y^{2} = \frac{- x - y + 2}{2}

(a, b) = (- \frac{1}{4}, - \frac{1}{4}), r = \frac{3}{2 2}

Solution steps

x^{2} + y^{2} = \frac{- x - y + 2}{2}

Rewrite

x^{2} + y^{2} = \frac{- x - y + 2}{2}

in the form of the standard circle equation

(x - (- \frac{1}{4}))^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{3}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{4}, - \frac{1}{4}), r = \frac{3}{2 2}

(X + 7)^{2} + (y - 1)^{2} = 9

(x^{2} - 2) + (y^{2} + 4) = 4

(x - 3)^{2} + (y + 1)^{2} = 49

(x + 7)^{2} + (y - 6)^{2} = 361

(x + 4)^{(2)} + (y - 2)^{(2)} = 25

What is x^2+y^2=(-x-y+2)/2 ?
The solution to x^2+y^2=(-x-y+2)/2 is Circle with (a,b)=(-1/4 ,-1/4),r= 3/(2sqrt(2))