What is x^2+y^2-2x-4=0 ?

The solution to x^2+y^2-2x-4=0 is Circle with (a,b)=(1,0),r=sqrt(5)

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x^2+y^2-2x-4=0

x^{2} + y^{2} - 2 x - 4 = 0

(a, b) = (1, 0), r = 5

Solution steps

x^{2} + y^{2} - 2 x - 4 = 0

Rewrite

x^{2} + y^{2} - 2 x - 4 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 5

4 x^{2} + 24 x + 4 y^{2} - 20 y = - 45

(x - 20)^{2} + (y - 24)^{2} = 625

(x + 3)^{2} + (y - 5)^{2} = 85

(x - 5.5)^{2} + (y - 0.5)^{2} = 3.53

x^{2} + y^{2} - 20 x - 10 y = 5925

What is x^2+y^2-2x-4=0 ?
The solution to x^2+y^2-2x-4=0 is Circle with (a,b)=(1,0),r=sqrt(5)