What is y^2=-x^2-4x+12 ?

The solution to y^2=-x^2-4x+12 is Circle with (a,b)=(-2,0),r=4

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y^2=-x^2-4x+12

y^{2} = - x^{2} - 4 x + 12

(a, b) = (- 2, 0), r = 4

Solution steps

y^{2} = - x^{2} - 4 x + 12

Rewrite

y^{2} = - x^{2} - 4 x + 12

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, 0), r = 4

x^{2} + y^{2} - 20 x + 8 y + 116 = 200

(x - 4)^{2} + (y - 1)^{2} = 36

x^{2} + 6 x + 9 + y^{2} - 10 y - 25 = 36

(x - 3)^{2} + (y + 7)^{2} = 9

y^{2} + x^{2} - 10 x + 4 y - 7 = 0

What is y^2=-x^2-4x+12 ?
The solution to y^2=-x^2-4x+12 is Circle with (a,b)=(-2,0),r=4