What is x^{(2)}+10x+y^{(2)}-2y=10 ?

The solution to x^{(2)}+10x+y^{(2)}-2y=10 is Circle with (a,b)=(-5,1),r=6

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x^{(2)}+10x+y^{(2)}-2y=10

x^{(2)} + 10 x + y^{(2)} - 2 y = 10

(a, b) = (- 5, 1), r = 6

Solution steps

x^{2} + 10 x + y^{2} - 2 y = 10

Rewrite

x^{2} + 10 x + y^{2} - 2 y = 10

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 1)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 5, 1), r = 6

x^{2} - 18 x + 29 + y^{2} = 0

3 x^{2} > 12 - 3 y^{2}

x^{2} + y^{2} - 16 x - 18 y + 109 = 0

(x - 4)^{2} + (y - 5)^{2} = 9

(x - 2)^{2} + y^{2} = 2

What is x^{(2)}+10x+y^{(2)}-2y=10 ?
The solution to x^{(2)}+10x+y^{(2)}-2y=10 is Circle with (a,b)=(-5,1),r=6