What is (x-3)^{(2)}+(y+2)^{(2)}=3 ?

The solution to (x-3)^{(2)}+(y+2)^{(2)}=3 is Circle with (a,b)=(3,-2),r=sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-3)^{(2)}+(y+2)^{(2)}=3

(x - 3)^{(2)} + (y + 2)^{(2)} = 3

(a, b) = (3, - 2), r = 3

Solution steps

(x - 3)^{2} + (y + 2)^{2} = 3

Rewrite

(x - 3)^{2} + (y + 2)^{2} = 3

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 3

x^{2} + y^{2} - 2 \geq 0

u^{2} + y^{2} = 146

4 x^{2} + 4 y^{2} + 0 = 16

x^{2} + y^{2} + 10 x - 16 y - 11 = 0

x^{2} + y^{2} - 2 x > 8

What is (x-3)^{(2)}+(y+2)^{(2)}=3 ?
The solution to (x-3)^{(2)}+(y+2)^{(2)}=3 is Circle with (a,b)=(3,-2),r=sqrt(3)