What is x^{(2)}+(y+1)^{(2)}=1 ?

The solution to x^{(2)}+(y+1)^{(2)}=1 is Circle with (a,b)=(0,-1),r=1

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x^{(2)}+(y+1)^{(2)}=1

x^{(2)} + (y + 1)^{(2)} = 1

(a, b) = (0, - 1), r = 1

Solution steps

x^{2} + (y + 1)^{2} = 1

Rewrite

x^{2} + (y + 1)^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 1))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, - 1), r = 1

(x - 2)^{2} + (y - 1)^{2} = 5

(x - 2)^{2} + (y - 1)^{2} = 2

(x - 2)^{2} + (y - 3)^{2} = 1^{2}

(x + 2)^{2} + (y + 3)^{2} = 81

0 = 2 - x^{2} - y^{2}

What is x^{(2)}+(y+1)^{(2)}=1 ?
The solution to x^{(2)}+(y+1)^{(2)}=1 is Circle with (a,b)=(0,-1),r=1