What is 5x^2+5y^2-10x+15y=10 ?

The solution to 5x^2+5y^2-10x+15y=10 is Circle with (a,b)=(1,-3/2),r=(sqrt(21))/2

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5x^2+5y^2-10x+15y=10

5 x^{2} + 5 y^{2} - 10 x + 15 y = 10

(a, b) = (1, - \frac{3}{2}), r = \frac{21}{2}

Solution steps

5 x^{2} + 5 y^{2} - 10 x + 15 y = 10

Rewrite

5 x^{2} + 5 y^{2} - 10 x + 15 y = 10

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{3}{2}))^{2} = (\frac{21}{2})^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{3}{2}), r = \frac{21}{2}

y^{2} = - x^{2} + 64

(x - 4)^{2} + (y + 5)^{2} = 3

(x - 0)^{2} + (y - 0)^{2} = 1 2^{2}

x^{2} + y^{2} = 4900

x^{2} + y^{2} - 18 x + 30 y + 297 = 0

What is 5x^2+5y^2-10x+15y=10 ?
The solution to 5x^2+5y^2-10x+15y=10 is Circle with (a,b)=(1,-3/2),r=(sqrt(21))/2