What is x^{(2)}+(y+2)^{(2)}=36 ?

The solution to x^{(2)}+(y+2)^{(2)}=36 is Circle with (a,b)=(0,-2),r=6

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x^{(2)}+(y+2)^{(2)}=36

x^{(2)} + (y + 2)^{(2)} = 36

(a, b) = (0, - 2), r = 6

Solution steps

x^{2} + (y + 2)^{2} = 36

Rewrite

x^{2} + (y + 2)^{2} = 36

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, - 2), r = 6

x^{2} + y^{2} + 2 x - 2 y - 1 = 4

x^{2} + y^{2} + 2 x - 2 y - 1 = 2

y^{2} = - (x + 2) (x - 3)

(x - 8)^{2} + (y - 9)^{2} = 3

2 y^{2} + 2 x^{2} = 1

What is x^{(2)}+(y+2)^{(2)}=36 ?
The solution to x^{(2)}+(y+2)^{(2)}=36 is Circle with (a,b)=(0,-2),r=6