What is (x-(-1))^2+(y-(-3))^2=16 ?

The solution to (x-(-1))^2+(y-(-3))^2=16 is Circle with (a,b)=(-1,-3),r=4

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(x-(-1))^2+(y-(-3))^2=16

(x - (- 1))^{2} + (y - (- 3))^{2} = 16

(a, b) = (- 1, - 3), r = 4

Solution steps

(x - (- 1))^{2} + (y - (- 3))^{2} = 16

Rewrite

(x - (- 1))^{2} + (y - (- 3))^{2} = 16

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 3), r = 4

x^{2} + y^{2} - 8 x + 6 y + 1 = 0

(x - 3)^{2} + (y + (- 1))^{2} = 16

x^{2} + 2 x + y^{2} - 6 y = - 7

4 x^{2} + 4 y^{2} + 4 x - 4 y + 1 = 0

2 x^{2} + 2 y^{2} + 16 - 40 = 0

What is (x-(-1))^2+(y-(-3))^2=16 ?
The solution to (x-(-1))^2+(y-(-3))^2=16 is Circle with (a,b)=(-1,-3),r=4