What is 3x^2+3y^2+12x-22y+35=0 ?

The solution to 3x^2+3y^2+12x-22y+35=0 is Circle with (a,b)=(-2, 11/3),r=(2sqrt(13))/3

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3x^2+3y^2+12x-22y+35=0

3 x^{2} + 3 y^{2} + 12 x - 22 y + 35 = 0

(a, b) = (- 2, \frac{11}{3}), r = \frac{2 13}{3}

Solution steps

3 x^{2} + 3 y^{2} + 12 x - 22 y + 35 = 0

Rewrite

3 x^{2} + 3 y^{2} + 12 x - 22 y + 35 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - \frac{11}{3})^{2} = (\frac{2 13}{3})^{2}

Therefore the circle properties are:

(a, b) = (- 2, \frac{11}{3}), r = \frac{2 13}{3}

2 x^{2} - 12 x + 2 y^{2} + 6 y = \frac{19}{2}

(x + 4)^{2} + (y - 2)^{2} = 3

(x + 4)^{2} + (y - 2)^{2} = 2

(x + 4)^{2} + (y - 2)^{2} = 1

(x - 6)^{2} + (y - 1)^{2} = 1

What is 3x^2+3y^2+12x-22y+35=0 ?
The solution to 3x^2+3y^2+12x-22y+35=0 is Circle with (a,b)=(-2, 11/3),r=(2sqrt(13))/3