What is ((x-9)^2)/2+((y-5)^2)/2 =1 ?

The solution to ((x-9)^2)/2+((y-5)^2)/2 =1 is Circle with (a,b)=(9,5),r=sqrt(2)

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((x-9)^2)/2+((y-5)^2)/2 =1

\frac{( x - 9 ) ^{2}}{2} + \frac{( y - 5 ) ^{2}}{2} = 1

(a, b) = (9, 5), r = 2

Solution steps

\frac{( x - 9 ) ^{2}}{2} + \frac{( y - 5 ) ^{2}}{2} = 1

Rewrite

\frac{( x - 9 ) ^{2}}{2} + \frac{( y - 5 ) ^{2}}{2} = 1

in the form of the standard circle equation

(x - 9)^{2} + (y - 5)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (9, 5), r = 2

[x - (- 2)]^{2} + (y - 3)^{2} = 3^{2}

\frac{( ( x + 2 ) ^{2} )}{4} + \frac{( ( y + 4 ) ^{2} )}{4} = 1

y^{2} = 36 - x^{2}

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

x^{2} - 6 x + y^{2} - 10 y = 2

What is ((x-9)^2)/2+((y-5)^2)/2 =1 ?
The solution to ((x-9)^2)/2+((y-5)^2)/2 =1 is Circle with (a,b)=(9,5),r=sqrt(2)