What is (x-6)(x-6)+(y-7)(y-7)=64 ?

The solution to (x-6)(x-6)+(y-7)(y-7)=64 is Circle with (a,b)=(6,7),r=8

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(x-6)(x-6)+(y-7)(y-7)=64

(x - 6) (x - 6) + (y - 7) (y - 7) = 64

(a, b) = (6, 7), r = 8

Solution steps

(x - 6) (x - 6) + (y - 7) (y - 7) = 64

Rewrite

(x - 6) (x - 6) + (y - 7) (y - 7) = 64

in the form of the standard circle equation

(x - 6)^{2} + (y - 7)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (6, 7), r = 8

36 = x^{2} + 12 + y^{2}

3 x^{2} + 6 x + 3 y^{2} = 0

(x + 2)^{2} + (y - 3)^{2} = 3.5

y^{2} + x^{2} - 18 x + 12 y + 101 = 0

(x + 4)^{2} + (y - 3)^{2} = 3

What is (x-6)(x-6)+(y-7)(y-7)=64 ?
The solution to (x-6)(x-6)+(y-7)(y-7)=64 is Circle with (a,b)=(6,7),r=8