What is x^2+8x+y^2-4y-29=0 ?

The solution to x^2+8x+y^2-4y-29=0 is Circle with (a,b)=(-4,2),r=7

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x^2+8x+y^2-4y-29=0

x^{2} + 8 x + y^{2} - 4 y - 29 = 0

(a, b) = (- 4, 2), r = 7

Solution steps

x^{2} + 8 x + y^{2} - 4 y - 29 = 0

Rewrite

x^{2} + 8 x + y^{2} - 4 y - 29 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 2)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 4, 2), r = 7

x^{2} + y^{2} - 2 x + 6 y - 10 = 0

3 x^{2} + 18 x + 3 y^{2} - 6 y = 18

4 x + 2 y = x^{2} + y^{2}

y^{(2)} + x^{(2)} - 4 x - 5 = 0

x^{2} + y^{2} = 3 x - y

What is x^2+8x+y^2-4y-29=0 ?
The solution to x^2+8x+y^2-4y-29=0 is Circle with (a,b)=(-4,2),r=7