What is x^2-4x+y^2+6y-3=0 ?

The solution to x^2-4x+y^2+6y-3=0 is Circle with (a,b)=(2,-3),r=4

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x^2-4x+y^2+6y-3=0

x^{2} - 4 x + y^{2} + 6 y - 3 = 0

(a, b) = (2, - 3), r = 4

Solution steps

x^{2} - 4 x + y^{2} + 6 y - 3 = 0

Rewrite

x^{2} - 4 x + y^{2} + 6 y - 3 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 4

(x - 4)^{2} + (y + 12)^{2} + (0 - 8) = 100

x^{2} - 2 x + 1 + y^{2} + y + 2 = \frac{11}{4}

(x - 6)^{2} + (y + 1)^{2} = 4

(x - 7)^{2} + (y + 5)^{2} = 4

x^{2} + y^{2} + 2 x - 10 y + 4 = 0

What is x^2-4x+y^2+6y-3=0 ?
The solution to x^2-4x+y^2+6y-3=0 is Circle with (a,b)=(2,-3),r=4