What is (x-(-2))^2+(y-1)^2=5^2 ?

The solution to (x-(-2))^2+(y-1)^2=5^2 is Circle with (a,b)=(-2,1),r=5

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(x-(-2))^2+(y-1)^2=5^2

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

(a, b) = (- 2, 1), r = 5

Solution steps

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

Rewrite

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 5

(x - 3)^{2} + (y + 13)^{2} = 9

x^{2} + y^{2} - 4 x + 2 y - 2 = 0

x^{2} + y^{2} + 9 x + 10 = 0

4 y^{2} - 72 y = 316 - 4 x^{2} - 24 x

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = 12

What is (x-(-2))^2+(y-1)^2=5^2 ?
The solution to (x-(-2))^2+(y-1)^2=5^2 is Circle with (a,b)=(-2,1),r=5