What is (X-5)^2+(y-4)^2=25 ?

The solution to (X-5)^2+(y-4)^2=25 is Circle with (a,b)=(5,4),r=5

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(X-5)^2+(y-4)^2=25

(X - 5)^{2} + (y - 4)^{2} = 25

(a, b) = (5, 4), r = 5

Solution steps

(X - 5)^{2} + (y - 4)^{2} = 25

Rewrite

(X - 5)^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(X - 5)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, 4), r = 5

(x + 5)^{2} + (y + 5)^{2} = 64

x^{2} + y^{2} - 8 x - 6 y = - 9

x^{2} + y^{2} + 4 x + 28 y = 175

4 x^{2} + 4 y^{2} - 16 x + 24 y - 51 = 0

(x + 1)^{2} + (y - 1)^{2} = 40

What is (X-5)^2+(y-4)^2=25 ?
The solution to (X-5)^2+(y-4)^2=25 is Circle with (a,b)=(5,4),r=5