What is x^2+y^2-2/3 x+8/3 y= 19/9 ?

The solution to x^2+y^2-2/3 x+8/3 y= 19/9 is Circle with (a,b)=(1/3 ,-4/3),r=2

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x^2+y^2-2/3 x+8/3 y= 19/9

x^{2} + y^{2} - \frac{2}{3} x + \frac{8}{3} y = \frac{19}{9}

(a, b) = (\frac{1}{3}, - \frac{4}{3}), r = 2

Solution steps

x^{2} + y^{2} - \frac{2}{3} x + \frac{8}{3} y = \frac{19}{9}

Rewrite

x^{2} + y^{2} - \frac{2}{3} x + \frac{8}{3} y = \frac{19}{9}

in the form of the standard circle equation

(x - \frac{1}{3})^{2} + (y - (- \frac{4}{3}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{3}, - \frac{4}{3}), r = 2

x^{2} + 14 x + y^{2} - 2 y - 50 = 0

(x - 2)^{2} + (y - 1.5)^{2} = 9

x^{2} + y^{2} + 2 x + 4 y - 31 = 0

x^{2} + y^{2} + 10 x - 2 y - 23 = 0

(x - 6)^{2} + (y - 3)^{2} = 20^{2}

What is x^2+y^2-2/3 x+8/3 y= 19/9 ?
The solution to x^2+y^2-2/3 x+8/3 y= 19/9 is Circle with (a,b)=(1/3 ,-4/3),r=2