What is (x-4)^{(2)}+(y-5)^{(2)}=49 ?

The solution to (x-4)^{(2)}+(y-5)^{(2)}=49 is Circle with (a,b)=(4,5),r=7

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(x-4)^{(2)}+(y-5)^{(2)}=49

(x - 4)^{(2)} + (y - 5)^{(2)} = 49

(a, b) = (4, 5), r = 7

Solution steps

(x - 4)^{2} + (y - 5)^{2} = 49

Rewrite

(x - 4)^{2} + (y - 5)^{2} = 49

in the form of the standard circle equation

(x - 4)^{2} + (y - 5)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (4, 5), r = 7

9 - x^{2} > y^{2}

x^{2} + y^{2} - 6 x - 4 y - 18 = 0

x^{2} + y^{2} + 2 x - 12 y + 12 = 0

x (x - 5) + (y - 2)^{2} = 0

(x - 3)^{2} + (y - 4)^{2} - 9 = 0

What is (x-4)^{(2)}+(y-5)^{(2)}=49 ?
The solution to (x-4)^{(2)}+(y-5)^{(2)}=49 is Circle with (a,b)=(4,5),r=7