What is x^2-10x+y^2+6y-30=0 ?

The solution to x^2-10x+y^2+6y-30=0 is Circle with (a,b)=(5,-3),r=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-10x+y^2+6y-30=0

x^{2} - 10 x + y^{2} + 6 y - 30 = 0

(a, b) = (5, - 3), r = 8

Solution steps

x^{2} - 10 x + y^{2} + 6 y - 30 = 0

Rewrite

x^{2} - 10 x + y^{2} + 6 y - 30 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 3))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, - 3), r = 8

x^{2} - 2 x + 1 + y^{2} + y + \frac{1}{11} = \frac{11}{4}

(- \frac{2}{5} - x)^{2} + (- \frac{6}{5} - y)^{2} = 10

9 x^{2} + 9 y^{2} - 24 x + 84 y + 65 = 0

(x - 1.5)^{2} + (y - 1)^{2} = 3

x^{2} + y^{2} - 6 x + 8 y - 12 = 0

What is x^2-10x+y^2+6y-30=0 ?
The solution to x^2-10x+y^2+6y-30=0 is Circle with (a,b)=(5,-3),r=8