What is x^2-4x+y^2+4y=-3 ?

The solution to x^2-4x+y^2+4y=-3 is Circle with (a,b)=(2,-2),r=sqrt(5)

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x^2-4x+y^2+4y=-3

x^{2} - 4 x + y^{2} + 4 y = - 3

(a, b) = (2, - 2), r = 5

Solution steps

x^{2} - 4 x + y^{2} + 4 y = - 3

Rewrite

x^{2} - 4 x + y^{2} + 4 y = - 3

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 2))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (2, - 2), r = 5

x^{2} + y^{2} + 8 x + 4 y - 4 = 0

X^{2} + Y^{2} - 5 X + 4 Y - 46 = 0

(x - 3)^{2} + (y - (- 2))^{2} = 5^{2}

x^{2} - 2 x + y^{2} + 6 y = 0

x^{2} + y^{2} - 10 x + 12 y = 3

What is x^2-4x+y^2+4y=-3 ?
The solution to x^2-4x+y^2+4y=-3 is Circle with (a,b)=(2,-2),r=sqrt(5)