What is (x^2)/(36)-(y^2)/(64)=1 ?

The solution to (x^2)/(36)-(y^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=6,b=8

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(x^2)/(36)-(y^2)/(64)=1

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

(h, k) = (0, 0), a = 6, b = 8

Solution steps

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 8

x^{2} + \frac{y ^{2}}{16} = 1

(x + 1)^{2} + (y - 2)^{2} = 9

\frac{( y + 1 ) ^{2}}{4} - (x - 5)^{2} = 4

25 x^{2} - 9 y^{2} = 225

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

What is (x^2)/(36)-(y^2)/(64)=1 ?
The solution to (x^2)/(36)-(y^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=6,b=8