What is x^2+y^2-18x+4y+60=0 ?

The solution to x^2+y^2-18x+4y+60=0 is Circle with (a,b)=(9,-2),r=5

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x^2+y^2-18x+4y+60=0

x^{2} + y^{2} - 18 x + 4 y + 60 = 0

(a, b) = (9, - 2), r = 5

Solution steps

x^{2} + y^{2} - 18 x + 4 y + 60 = 0

Rewrite

x^{2} + y^{2} - 18 x + 4 y + 60 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (9, - 2), r = 5

x^{2} + y^{2} - 10 x - 16 y - 9 = 0

x^{2} + y^{2} = 17 - 16

x^{2} + y^{2} - 10 x + 20 y + 100 = 0

(x + 8)^{2} + (y + 6)^{2} = 100

x^{2} = 22 - y^{2}

What is x^2+y^2-18x+4y+60=0 ?
The solution to x^2+y^2-18x+4y+60=0 is Circle with (a,b)=(9,-2),r=5