What is x^2+y^2-25x-25y+100=0 ?

The solution to x^2+y^2-25x-25y+100=0 is Circle with (a,b)=(25/2 , 25/2),r=(5sqrt(17))/(sqrt(2))

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x^2+y^2-25x-25y+100=0

x^{2} + y^{2} - 25 x - 25 y + 100 = 0

(a, b) = (\frac{25}{2}, \frac{25}{2}), r = \frac{5 17}{2}

Solution steps

x^{2} + y^{2} - 25 x - 25 y + 100 = 0

Rewrite

x^{2} + y^{2} - 25 x - 25 y + 100 = 0

in the form of the standard circle equation

(x - \frac{25}{2})^{2} + (y - \frac{25}{2})^{2} = (\frac{5 17}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{25}{2}, \frac{25}{2}), r = \frac{5 17}{2}

4 x^{2} + 4 y^{2} + 24 x - 32 y + 75 = 0

x^{2} + y^{2} - 3.11 x - 10.67 y - 62.22 = 0

x^{2} + y^{2} - 5 x = 12 - 6 y

x^{2} + y^{2} + 8 x - 8 y - 18 = 0

(x + 1)^{2} + (y + 4)^{2} = 100

What is x^2+y^2-25x-25y+100=0 ?
The solution to x^2+y^2-25x-25y+100=0 is Circle with (a,b)=(25/2 , 25/2),r=(5sqrt(17))/(sqrt(2))