What is 8x^2+8y^2-24+64y=37 ?

The solution to 8x^2+8y^2-24+64y=37 is Circle with (a,b)=(0,-4),r=(3sqrt(21))/(2sqrt(2))

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8x^2+8y^2-24+64y=37

8 x^{2} + 8 y^{2} - 24 + 64 y = 37

(a, b) = (0, - 4), r = \frac{3 21}{2 2}

Solution steps

8 x^{2} + 8 y^{2} - 24 + 64 y = 37

Rewrite

8 x^{2} + 8 y^{2} - 24 + 64 y = 37

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = (\frac{3 21}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = \frac{3 21}{2 2}

5 = (x + 2)^{2} + (y - 3)^{2}

x^{2} + y^{2} - 8 x - 10 y + 8 = 0

x^{2} + y^{2} - 4 x + 16 y + 4 = 0

x^{2} + y^{2} = 96

x^{2} + y^{2} = 99

What is 8x^2+8y^2-24+64y=37 ?
The solution to 8x^2+8y^2-24+64y=37 is Circle with (a,b)=(0,-4),r=(3sqrt(21))/(2sqrt(2))