What is (x+2)^2+(y-1/2)^2= 97/20 ?

The solution to (x+2)^2+(y-1/2)^2= 97/20 is Circle with (a,b)=(-2, 1/2),r=sqrt(97/20)

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(x+2)^2+(y-1/2)^2= 97/20

(x + 2)^{2} + (y - \frac{1}{2})^{2} = \frac{97}{20}

(a, b) = (- 2, \frac{1}{2}), r = \frac{97}{20}

Solution steps

(x + 2)^{2} + (y - \frac{1}{2})^{2} = \frac{97}{20}

Rewrite

(x + 2)^{2} + (y - \frac{1}{2})^{2} = \frac{97}{20}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - \frac{1}{2})^{2} = (\frac{97}{20})^{2}

Therefore the circle properties are:

(a, b) = (- 2, \frac{1}{2}), r = \frac{97}{20}

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What is (x+2)^2+(y-1/2)^2= 97/20 ?
The solution to (x+2)^2+(y-1/2)^2= 97/20 is Circle with (a,b)=(-2, 1/2),r=sqrt(97/20)