What is x^2+y^2-2x+1=4(x^2+y^2+2x+1) ?

The solution to x^2+y^2-2x+1=4(x^2+y^2+2x+1) is Circle with (a,b)=(-5/3 ,0),r= 4/3

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x^2+y^2-2x+1=4(x^2+y^2+2x+1)

x^{2} + y^{2} - 2 x + 1 = 4 (x^{2} + y^{2} + 2 x + 1)

(a, b) = (- \frac{5}{3}, 0), r = \frac{4}{3}

Solution steps

x^{2} + y^{2} - 2 x + 1 = 4 (x^{2} + y^{2} + 2 x + 1)

Rewrite

x^{2} + y^{2} - 2 x + 1 = 4 (x^{2} + y^{2} + 2 x + 1)

in the form of the standard circle equation

(x - (- \frac{5}{3}))^{2} + (y - 0)^{2} = (\frac{4}{3})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{3}, 0), r = \frac{4}{3}

x^{2} + y^{2} - 8 x + 12 y + 48 = 0

x^{2} + y^{2} = 11 4^{2}

a^{2} + b^{2} = 40

a^{2} + b^{2} = 49

2 x^{2} + 2 y^{2} - x = 0

What is x^2+y^2-2x+1=4(x^2+y^2+2x+1) ?
The solution to x^2+y^2-2x+1=4(x^2+y^2+2x+1) is Circle with (a,b)=(-5/3 ,0),r= 4/3