What is x^2+4x=10-y^2 ?

The solution to x^2+4x=10-y^2 is Circle with (a,b)=(-2,0),r=sqrt(14)

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x^2+4x=10-y^2

x^{2} + 4 x = 10 - y^{2}

(a, b) = (- 2, 0), r = 14

Solution steps

x^{2} + 4 x = 10 - y^{2}

Rewrite

x^{2} + 4 x = 10 - y^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 0)^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 0), r = 14

x^{2} + y^{2} = 6 x + 6 y

x^{2} + y^{2} = 9

x^{2} + y^{2} - 2 x - 6 y - 6 = 0

x^{2} + y^{2} = 49

x^{2} + y^{2} = 4

What is x^2+4x=10-y^2 ?
The solution to x^2+4x=10-y^2 is Circle with (a,b)=(-2,0),r=sqrt(14)