Solution
center
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:
Popular Examples
center 4(x^2+y^2-x-2y)=1center center x^2+y^2-4x=0center center x^2+y^2+4x-6y-3=0center center 9x^2+9y^2+18x-18y+14=0center center (x+3)^2-49=-y^2center
Frequently Asked Questions (FAQ)
What is the center 8x+x^2-2y=64-y^2 ?
The center 8x+x^2-2y=64-y^2 is (-4,1)