What is the center 2x^2+2y^2-14x+18y=7 ?

The center 2x^2+2y^2-14x+18y=7 is (7/2 ,-9/2)

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center 2x^2+2y^2-14x+18y=7

center

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

(\frac{7}{2}, - \frac{9}{2})

Solution steps

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

Rewrite

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - (- \frac{9}{2}))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, - \frac{9}{2}), r = 6

And the center is:

(\frac{7}{2}, - \frac{9}{2})

4 x^{2} + 4 y^{2} - 16 x - 24 y + 51 = 0

x^{2} + y^{2} + 4 x - 2 y - 4 = 0

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

x^{2} + y^{2} - 12 x - 10 y = - 12

x^{2} + y^{2} = 5

What is the center 2x^2+2y^2-14x+18y=7 ?
The center 2x^2+2y^2-14x+18y=7 is (7/2 ,-9/2)