What is the center 3(x-4)^2+3y^2=54 ?

The center 3(x-4)^2+3y^2=54 is (4,0)

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center 3(x-4)^2+3y^2=54

center

3 (x - 4)^{2} + 3 y^{2} = 54

(4, 0)

Solution steps

3 (x - 4)^{2} + 3 y^{2} = 54

Rewrite

3 (x - 4)^{2} + 3 y^{2} = 54

in the form of the standard circle equation

(x - 4)^{2} + (y - 0)^{2} = (32)^{2}

Therefore the circle properties are:

(a, b) = (4, 0), r = 32

And the center is:

(4, 0)

(x - 4)^{2} + (y + 1)^{2} = 9

2 x^{2} + 2 y^{2} + 2 x - y = 0

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

(x - 3)^{2} + (y + 1)^{2} = 16

x^{2} + (y - 4)^{2} = 49